The Bohr exciton radius (\(a_B\)) is given by the formula: \[ a_B = \frac{\epsilon \hbar^2}{\mu e^2} \] where: - \(\epsilon\) is the dielectric constant of the material, - \(\hbar\) is the reduced Planck's constant, - \(\mu\) is the reduced mass of the electron-hole pair, - \(e\) is the elementary charge.
